Q:

A large community collage has professors and lecturers. the total number of faculty members is 136. the school reported that they had 6 professors for every 11 lecturers. how many professors does the community collage employ?​

Accepted Solution

A:
Answer:88Step-by-step explanation:Lets call L the number if lecturers and P the professors. As all of them together sum 136:P + L = 136Then, as for every 11 lecturers they have 6 professors, we know that:6 P = 11 LIf we divide both sides of this equation by 6:6P / 6 = 11L / 6P = (11/6)LSo we have the equivalence of 1 Professor in Lecturers. If we replace this equation on our first equation:P + L = 136(11/6) L + L = 136 or what is the same:(11/6) L + (6/6) L = 136(11+6)/6 L = 13617/6 Β L = 136 If we multiply both sides by 6/17(17/6) L * (6/17) = 136 * 6/17L = 48So, we replace the number of lecturers to find P:P + L = 136P = 136 - LP = 136 - 48P = 88The college employs 88 professors